Hey there...
I have a script that allows someone to add the service times for a chuch into database using time(). There are normally about three church services on the same day.
Basically there is a form where they select the day, month and year. When adding the service to the database, I use this code to convert the service times into timestamp:
PHP Code:
$service_datday = mktime(0, 0, 0, $HTTP_POST_VARS[month], $HTTP_POST_VARS[day], $HTTP_POST_VARS[year]);
$service_dattime = mktime($hour, $HTTP_POST_VARS[minute], 0, $HTTP_POST_VARS[month], $HTTP_POST_VARS[day], $HTTP_POST_VARS[year]);
The database tables:
Code:
service_intid
service_strname
service_datday
service_dattime
That all works fine... But now with the question...
Basically what I want to do is select four of the up coming services from the database. That's easy except some days, like I said above, have three services on that one day... So three of the service_datday would be exactly the same because the service is on the same day. I only want to select one of those three from the database.
So basically I would need something like this... This is just a guess of how it would work...
PHP Code:
$query = mysql_query("select * from {$tbl_name}services order by unique(service_datday) desc") or die("<b>MySQL Error:</b> ".mysql_error());
while($row = mysql_fetch_array($query)) {
ect...
I'm not sure what to use instead of
unique(service_datday).
Hopefully that all makes sense
Cheers